A body is released from a height equal to the radius (R) of the Earth. The velocity of the body when it strikes the surface of the Earth will be (Given g = acceleration due to gravity on the Earth.) [2023]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
A body is released from a height equal to the radius (R) of the Earth. The velocity of the body when it strikes the surface of the Earth will be (Given g = acceleration due to gravity on the Earth.) [2023]

1 $\sqrt{g R}$

2 $\sqrt{4 g R}$

3 $\sqrt{2 g R}$

4 $\sqrt{\frac{g R}{2}}$

Ans.
(1)

$By conservation of mechanical energy$

$U_{i} + K_{i} = U_{f} + K_{f}$

$- \frac{G M m}{2 R} + 0 = - \frac{G M m}{R} + \frac{1}{2} m v^{2}$

$\frac{G M m}{2 R} = \frac{1}{2} m v^{2}$

$v = \sqrt{\frac{G M}{R}} = \sqrt{g R}$

Want Us to Email you About Special Offers & Updates?