A body covers a distance of 4 m in 3rd second and 12 m in 5th second. If the motion is uniformly accelerated, how far will it travel in the next 3 seconds?

Question

Smart Achievers · Accepted Answer

(4)

$S_{3} = u + \frac{a}{2} (2 \times 3 - 1) = 4 or u + \frac{5}{2} a = 4$

$S_{5} = u + \frac{a}{2} (2 \times 5 - 1) = 12 or u + \frac{9}{2} a = 12$

On solving, $u = - 6 m s^{- 1},$ $a = 4 m s^{- 2}$

Distance travelled in next 3 seconds is $S_{8} - S_{5}$

$= [- 6 \times 8 + \frac{1}{2} \times 4 \times {(8)}^{2}] - [- 6 \times 5 + \frac{1}{2} \times 4 \times {(5)}^{2}]$

$= 80 - 20 = 60 m$

Solution

Q.
A body covers a distance of 4 m in 3rd second and 12 m in 5th second. If the motion is uniformly accelerated, how far will it travel in the next 3 seconds

1 10 m

2 30 m

3 40 m

4 60 m

Want Us to Email you About Special Offers & Updates?