Q.

A block with mass M is connected by a massless spring with stiffness constant k to a rigid wall and moves without friction on a horizontal surface. The block oscillates with small amplitude A about an equilibrium position x0. Consider two cases: (i) when the block is at x0, and (ii) when the block is at x=x0+A. In both the cases, a particle with mass m(m<M) is softly placed on the block after which they stick to each other. Which of the following statement(s) is (are) true about the motion after the mass m is placed on the mass M                  [2016]

1 The amplitude of oscillation in the first case changes by a factor of Mm+M, whereas in the second case it remains unchanged.  
2 The final time period of oscillation in both the cases is same.  
3 The total energy decreases in both the cases.  
4 The instantaneous speed at x0 of the combined masses decreases in both the cases.  

Ans.

(1, 2, 4)

Case (i) : Applying principle of conservation of linear momentum.

MV1=(M+m)V2         .... (i)

M(A1×ω1)=(M+m)(A2×ω2)

  MA1×KM=(M+m)A2×KM+m

 A2=MM+mA1A2A1=MM+m

Also, E1=12MV12

and E2=12(M+m)V22          (V2=(MM+m)V1 from eq (i))

E2=12(M+m)(MM+m)2V12

=12(MM+m)V12

Clearly,  E1>E2

The new time period  T2=2m+MK

Instantaneous speed at X0 of the combined masses  V2=MV1M+m<V1

Case (ii) : The new time period T2=2m+MK

Also, A2=A1    and    E2=E1

In this case also, instantaneous speed at X0 of the combined masses decreases.