Q.

A block of mass m1=1 kg and another mass m2=2 kg, are placed together (see figure) on an inclined plane with angle of inclination θ. Various values of θ are given in List-I. The coefficient of friction between the block m1 and plane is always zero. The coefficient of static and dynamic friction between the block m2 and the plane are equal to μ=0.3. In List-II expressions for the friction on block m2 are given. Match the correct expression of the friction in List-II with the angles given in List-I, and choose the correct option. The acceleration due to gravity is denoted by g.

Useful information: tan(5.5°)0.1; tan(11.5°)0.2; tan(16.5°)0.3                           [2014]

  List - I   List - II
P. θ=5° 1. m2gsinθ
Q. θ=10° 2. (m1+m2)gsinθ
R. θ=15° 3. μm2gcosθ
S. θ=20° 4. μ(m1+m2)gcosθ

Code:

1 P-1, Q-1, R-1, S-3  
2 P-2, Q-2, R-2, S-3  
3 P-2, Q-2, R-2, S-4  
4 P-2, Q-2, R-3, S-3  

Ans.

(4)

Block will not slip or will be at rest if (m1+m2)gsinθμm2gcosθ

tanθμm2g(m1+m2)g

tanθμm2m1+m2

tanθ0.3×21+215

tanθ0.2  i.e.,  θ11.5°

i.e., If the angle θ<11.5°, the frictional force is less than μN2=μm2g=0.3×2×g=0.6g

and is equal to (m1+m2)gsinθ.

Blocks will not slip on the inclined plane and friction is static.

At θ>11.5°, the bodies start moving on the inclined plane and friction is kinetic and equal to μm2gcosθ.