A block of mass 5 kg is placed at rest on a table of rough surface. Now, if a force of 30 N is applied in the direction parallel to the surface of the table, the block slides through a distance of 50 m in an interval of time 10 s. Coefficient of kinetic f

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Solution

Q.
A block of mass 5 kg is placed at rest on a table of rough surface. Now, if a force of 30 N is applied in the direction parallel to the surface of the table, the block slides through a distance of 50 m in an interval of time 10 s. Coefficient of kinetic friction is (given g = 10 ${ms}^{- 2}$ ) [2023]

1 0.60

2 0.75

3 0.50

4 0.25

Ans.
(3)

$S = u t + \frac{1}{2} a t^{2}$

$50 = 0 + \frac{1}{2} \times a \times 100$

$\Rightarrow a = 1 {m/s}^{2}$

$F - μ m g = m a$

$30 - μ \times 50 = 5 \times 1$

$\Rightarrow 50 μ = 25$

$\Rightarrow μ = \frac{1}{2}$

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