A block of mass 2 kg is placed on an inclined rough surface AC (as shown in figure) of coefficient of friction . If g = 10 , the net force (in N) on the block will be [2023]

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Solution

Q.
A block of mass 2 kg is placed on an inclined rough surface AC (as shown in figure) of coefficient of friction $μ$ . If g = 10 ${ms}^{- 2}$ , the net force (in N) on the block will be [2023]

1 $10 \sqrt{3}$

2 zero

3 10

4 20

Ans.
(2)

The given parameters are, Coefficient of friction, $μ = \frac{1}{\sqrt{3}}$ and angle of friction is $30 ° .$

$F_{net} = m g \sin θ - μ m g \cos θ$

$= m g \sin 30 ° - μ m g \cos 30 °$

$= \frac{1}{2} m g - \frac{1}{\sqrt{3}} m g \frac{\sqrt{3}}{2} = \frac{1}{2} m g - \frac{1}{2} m g = 0$

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