A 90 kg body placed at 2R distance from surface of earth experiences gravitational pull of (R = Radius of earth

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Solution

Q.
A 90 kg body placed at 2R distance from surface of earth experiences gravitational pull of (R = Radius of earth, $g = 10 m s^{- 2}$ ) [2024]

1 100 N

2 300 N

3 120 N

4 225 N

Ans.
(1)

Acceleration due to gravity at height $h$ from earth's surface

$g_{h} = \frac{G M}{{(R + h)}^{2}}$

$g_{h} = \frac{G M}{9 R^{2}} = \frac{g_{s}}{9} (∵ h = 2 R)$

Here $g_{s} =$ gravitational acceleration at surface

Gravitational Pull $m g_{s} = 90 \times \frac{g_{s}}{9} = 100 N$

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