A 100 resistance and a capacitor of 100 reactance are connected in series across a 220 V source. When the capacitor is 50% charged, the peak value of the displacement current is [2016]

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Solution

Q.
A 100 $Ω$ resistance and a capacitor of 100 $Ω$ reactance are connected in series across a 220 V source. When the capacitor is 50% charged, the peak value of the displacement current is [2016]

1 2.2 A

2 11 A

3 4.4 A

4 $11 \sqrt{2}$ A

Ans.
(1)

Here, $R = 100 Ω, X_{C} = 100 Ω$

Net impedance, $Z = \sqrt{R^{2} + X_{C}^{2}} = 100 \sqrt{2} Ω$

Peak value of displacement current = Maximum conduction current in the circuit

$= \frac{ε_{0}}{Z} = \frac{220 \sqrt{2}}{100 \sqrt{2}} = 2.2 A$

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