A 0.4 kg mass takes 8 s to reach ground when dropped from a certain height 'P' above surface of earth. The loss of potential energy in the last second of fall is ______ J. [] ?[2023]

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Solution

Q.
A 0.4 kg mass takes 8 s to reach ground when dropped from a certain height 'P' above surface of earth. The loss of potential energy in the last second of fall is ______ J. [ ${Take g = 10 m/s}^{2}$ ] [2023]

Ans.
(300)

$Displacement is 8^{th} sec.$

$S_{8} = 0 + \frac{1}{2} \times 10 \times (2 \times 8 - 1)$

$S_{8} = 5 \times 15$

$Δ U = 0.4 \times 10 \times 5 \times 15 = 20 \times 15 = 300$

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