Q.

96cosπ33cos2π33cos4π33cos8π33cos16π33 is equal to               [2023]

1 3  
2 2  
3 1  
4 4  

Ans.

(1)

We know that,

cosπ33cos2π33cos4π33cos8π33cos16π33=sin32π3332sinπ33

sin(π-π33)32·sinπ33=sinπ3332·sinπ33=132

  96cosπ33cos2π33cos4π33cos8π33cos16π33=9632=3