Q.

∫-π/4π/4dx1+cos2x  is equal to:

1 1  
2 2  
3 3  
4 4  

Ans.

(1)

Ans.       1

Explanation :

Let        I=∫-π/4π/4dx1+cos2x

              =∫-π/4π/4dx2cos2x

              =12∫-π/4π/4sec2x dx=∫0π/4sec2x dx

              =[tanx]0π/4=tanπ4-tan0

              =1-0=1