∫-π/4π/4dx1+cos2x is equal to:
(1)
Ans. 1
Explanation :
Let I=∫-π/4π/4dx1+cos2x
=∫-π/4π/4dx2cos2x
=12∫-π/4π/4sec2x dx=∫0π/4sec2x dx
=[tanx]0π/4=tanπ4-tan0
=1-0=1