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Solution


Q.

3 chairs and 1 table cost Rs 900; whereas 5 chairs and 3 tables cost Rs 2,100. If the cost of 1 chair is Rs x and the cost of 1 table is Rs y, then the situation can be represented algebraically as
1 3x + y = 900, 3x + 5y = 2100  
2 x + 3y = 900, 3x + 5y = 2100  
3 3x + y = 900, 5x + 3y = 2100  
4 x + 3y = 900, 5x + 3y = 2100  

Ans.

(3)

Given situations can be represented algebraically as:

3x + y = 900 and 5x + 3y = 2100