0.53 g of an organic compound (x) when heated with excess of nitric acid (concentrated) and then with silver nitrate gave 0.75 g of silver bromide precipitate. 1.0 g of (x) gave 1.32 g of ? gas on combustion. The percentage of hydrogen in the compound (x)

Question

0.53 g of an organic compound (x) when heated with excess of nitric acid (concentrated) and then with silver nitrate gave 0.75 g of silver bromide precipitate. 1.0 g of (x) gave 1.32 g of $C O_{2}$ gas on combustion. The percentage of hydrogen in the compound (x) is ____%. [Nearest Integer]

[Given: Molar mass in g ${mol}^{- 1}$ H : 1, C : 12, Br : 80, Ag : 108, O : 16 ;
Compound (x) : $C_{x} H_{y} B r_{z}$ ] [2026]

Smart Achievers · Accepted Answer

(4)

$\begin{matrix} C_{x} H_{y} {Br}_{z} & \to & {CO}_{2} \\ 1 g & 1.32 g \end{matrix}$

$% C = \frac{1.32 \times 12}{44 \times 1} \times 100 = 36 %$

$\begin{matrix} C_{x} H_{y} {Br}_{z} & \to & AgBr \\ 0.53 g & 0.75 g \end{matrix}$

$% Br = \frac{0.75 \times 80}{188 \times 0.53} \times 100 = 60.2 %$

$% H = 100 - (36 + 60.2)$

$% H \approx 4 %$

Solution

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Solution

Ans. (4) CxHyBrz→CO21 g1.32 g %C=1.32×1244×1×100=36% CxHyBrz→AgBr0.53 g0.75 g %Br=0.75×80188×0.53×100=60.2% %H=100-(36+60.2) %H≈4%

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