0 / 8 tan 2 ( 2 x ) ? d x is equal to:

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Other Competitive Exams

NDA

NDA

MATHS

Courses

Class Room Courses
Online Live Courses
Online Recorded Courses

ONLINE COURSES

More

Solution

Q.
$\int_{0}^{π / 8} \tan^{2} (2 x) d x$ is equal to:

1 $\frac{4 - π}{8}$

2 $\frac{4 + π}{8}$

3 $\frac{4 - π}{4}$

4 $\frac{4 - π}{2}$

Ans.
(1)

Ans. $\frac{4 - π}{8}$

Explanation :

$\int_{0}^{π / 8} \tan^{2} (2 x) d x = \int_{0}^{π / 8} (\sec^{2} (2 x) - 1) d x$

$= {[\frac{\tan (2 x)}{2} - x]}_{0}^{π / 8}$

$= \frac{1}{2} - \frac{π}{8} + 0 - 0 = \frac{4 - π}{8}$

Want Us to Email you About Special Offers & Updates?