Q.

∫0π/2cosx esinx  dx  is equal to:

1 e+1  
2 e-1  
3 e  
4 -e  

Ans.

(2)

Ans.       e-1

Explanation :

Let                    I=∫0π/2cosx esinx dx

Put            sinx=t

⇒   cosx dx=dt

As x→0, then t→0,

and as x→π2, then t→1

∴          I=∫01et dt=[et]01

                =e1-e0

                =e-1