∫0π/2cosx esinx dx is equal to:
(2)
Ans. e-1
Explanation :
Let I=∫0π/2cosx esinx dx
Put sinx=t
⇒ cosx dx=dt
As x→0, then t→0,
and as x→π2, then t→1
∴ I=∫01et dt=[et]01
=e1-e0
=e-1