Q 21 :

If force (F), velocity (V) and time (T) are considered as fundamental physical quantities, then dimensional formula of density will be:

  • FV-2T2

     

  • FV-4T-2

     

  • FV4T2

     

  • F2V-2T6

     

(2)

M1L-3T0=(M1LT-2)a(LT-1)bTc    

a=1, b=-4, c=-2



Q 22 :

The electric resistance of medium depends upon permeability (μ) and permittivity (ε) as given below R∝(μ)a(ε)b. If a-b=N. The value of N is ...........



(1)

ML2T-3A-2=[MLT-2A-2]a[M-1L-3T4A2]b

a-b=1

a-3b=2

a=12,  b=-12



Q 23 :

An expression of energy density is given by u=αβsin(αxkt). Where α,β are constants, x is displacement, k is Boltzmann constant and t is the absolute temperature. The dimensions of β will be:

  • [ML2T-2θ-1]

     

  • [M0L2T-2]

     

  • [M0L0T0]

     

  • [M0L2T0]

     

(4)

sin(αxkt)=Dimensionless

∴ α[L][ML2T-2]=[M0L0T0]⇒α=[MLT-2]

αβ=EnergyVolume=[ML2T-2][L3]

⇒β=[MLT-2][L3][ML2T-2]

=[M0L2T0]



Q 24 :

If F is force, V is velocity, H is latent heat, and s is specific heat, then match the quantity given in Column I with the dimensions given in Column II.

  Column I   Column II
i. F a. L2T-2
ii. V b. L2T-2K-1
iii. H c. MLT-2
iv. S d. LT-1

 

  • i → c, ii → d, iii → a, iv → b

     

  • i → a, ii → b, iii → c, iv → d

     

  • i → d, ii → a, iii → b, iv → c

     

  • i → c, ii → a, iii → b, iv → d

     

(1)

iii.   [H]=[HeatMass]=ML2T-2M=L2T-2

iv.   [s]=[HeatMass×Temperature]=ML2T-2MK=L2T-2K-1



Q 25 :

Match list I with list II:

  List I   List II
a) Torque (i) MLT-1
b) Impulse (ii) MT-2
c) Tension (iii) ML2T-2
d) Surface tension (iv) MLT-2

 

Choose the most appropriate answer from the options given below:

  • a)-(iii), b)-(iv), c)-(i), d)-(ii)

     

  • a)-(iii), b)-(i), c)-(iv), d)-(ii)

     

  • a)-(i), b)-(iii), c)-(iv), d)-(ii)

     

  • a)-(ii), b)-(i), c)-(iv), d)-(iii)

     

(2)

Torque-ML2T-2

Impulse-MLT-1

Tension-MLT-2

Surface tension-MT-2