The quantum numbers of four electrons are given below.
I.
II.
III.
IV.
The correct decreasing order of energy of these electrons is [2024]
IV > II > III > I
I > III > II > IV
III > I > II > IV
I > II > III > IV
(2)
The increasing order of energy is
Orbital | ||
4 | 2 | |
3 | 2 | |
4 | 1 | |
3 | 1 |
Thus,
Match List I with List II. [2024]
List I | List II | ||
(Quantum number) | (Information provided) | ||
A. | I. | shape of orbital | |
B. | II. | size of orbital | |
C. | III. | orientation of orbital | |
D. | IV. | orientation of spin of electron |
Choose the correct answer from the options given below:
(2)
Principal quantum no. determines the size of orbital. Azimuthal quantum no. gives idea of shape of orbitals. Magnetic quantum no. gives information about the spatial orientation of orbitals while spin quantum no. gives information about the direction of spin of the electron present in any orbital.
Incorrect set of quantum numbers from the following is [2023]
(2)
For a given value of , has values.
For , the number of values is [2(2) + 1] = 5. But in set (b), only four values of are given. The values of range from to including 0.
Hence, the possible values for the given orbital are
Given below are two statements: [2023]
Statement I: The value of wave function, depends upon the coordinates of the electron in the atom.
Statement II: The probability of finding an electron at a point within an atom is proportional to the orbital wave function.
In the light of the above statements, choose the correct answer from the options given below:
Statement I is true but Statement II is false.
Statement I is false but Statement II is true.
Both Statement I and Statement II are true.
Both Statement I and Statement II are false.
(1)
The square of the wave function at a point gives the probability density of the electron at that point.
The relation between , ( = the number of permissible values of magnetic quantum number ()) for a given value of azimuthal quantum number (), is [2023]
(3)
Identify the incorrect statement from the following. [2022]
All the five 5d orbitals are different in size when compared to the respective 4d orbitals.
All the five 4d orbitals have shapes similar to the respective 3d orbitals.
In an atom, all the five 3d orbitals are equal in energy in free state.
The shapes of , and orbitals are similar to each other; and and are similar to each other.
(4)
The shapes of , , and are similar to each other, whereas that of is different from others. All five 3d orbitals are equivalent in energy. The d-orbitals for which is greater than 3 also have shapes similar to 3d-orbital but differ in energy and size.
and orbitals are arranged in the order of decreasing energy. The correct option is [2019]
(2)
Higher the value of for an orbital, higher is its energy. However, if two different types of orbitals have same value of , the orbital with lower value of has lower energy. Therefore, decreasing order of energy of the given orbitals is
Orbital having 3 angular nodes and 3 total nodes is [2019]
(3)
Number of spherical/radial nodes in any orbital
Number of planar/angular nodes in orbital
Total number of nodes in any orbital =
Thus, the orbital is .
Which one is a wrong statement? [2018]
Total orbital angular momentum of electron in s-orbital is equal to zero.
An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers.
The electronic configuration of N atom is
[IMAGE 6]
The value of for is zero.
(3)
According to Hund’s rule of maximum multiplicity, the correct configuration of ‘N’ is
[IMAGE 7]
Which one is the wrong statement? [2017]
The uncertainty principle is
Half filled and fully filled orbitals have greater stability due to greater exchange energy, greater symmetry and more balanced arrangement.
The energy of 2s-orbital is less than the energy of 2p-orbital in case of hydrogen like atoms.
de-Broglie's wavelength is given by , where = mass of the particle, = group velocity of the particle.
(3)
In case of hydrogen like atoms, energy depends on the principal quantum number only. Hence, 2s-orbital will have energy equal to 2p-orbital.