NEET PYQ: Structure of Atom – Important Questions for Chemistry Preparation

(2)

Bohr radius, $a_{0} = 52.9$ pm

$n = 2, r_{n} = n^{2} a_{0} = {(2)}^{2} a_{0} = 4 \times 52.9 pm = 211.6 pm$

The angular momentum of an electron in a given stationary state can be expressed as in equation,

$m v r = n \cdot \frac{h}{2 π} = 2 \times \frac{h}{2 π} = \frac{h}{π} \Rightarrow m v r π = h$ ...(i)

de Broglie equation,

$λ = \frac{h}{m v}; λ m v = h$ ...(ii)

From equations (i) and (ii), we get $λ = π r$

Putting the value of $r,$ $λ = 211.6 π$ pm

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