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Solution


Q.

Orbital having 3 angular nodes and 3 total nodes is          [2019]
1 5p  
2 3d  
3 4f  
4 6d  

Ans.

(3)

Number of spherical/radial nodes in any orbital =n-l-1

Number of planar/angular nodes in orbital =l=3

∴   Total number of nodes in any orbital = n-1=3

∴  n=4

Thus, the orbital is 4f.