Q 1 :    

We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentration 0.1 M, 0.01 M and 0.001 M, respectively. The value of van’t Hoff factor (i) for these solutions will be in the order:                     [2024]

  • iA<iB<iC

     

  • iA<iC<iB

     

  • iA=iB=iC

     

  • iA>iB>iC

     

(A)

              Van't Hoff factor (i) is given by:

              i=Number of particles after dissociationNumber of particles before dissociation

             With dilution, degree of dissociation increases hence i increases with dilution. Hence i for A (0.1M NaCl), B (0.01M NaCl) and C (0.001M NaCl) is: iA<iB<iC

 



Q 2 :    

A solution containing 10 g of an electrolyte AB2 in 100 g of water boils at 100.52C°. The degree of ionization of the electrolyte (α) is _____×10-1. (nearest integer)

 

[Given : Molar mass of AB2=200g mol-1Kb (molal boiling point elevation const. of water) = 0.52 K kg mol-1, boiling point of water = 100°C; AB2 ionises as AB2A2++2B-]                [2024]



(5)

                ΔTb=Tb-Tb°=(100.52-100)K=0.52K

                imkb=0.52K

                iwsolute×1000Msolute×Wsolvent(in g)kb=0.52K

                i10×1000200×100×0.52=0.52

                i=2

                AB2A2++2B-

               i=1+(n-1)α

              2=1+(3-1)α

             α=0.5=5×10-1