Q.

If A2B is 30% ionised in an aqueous solution, then the value of van’t Hoff factor (i) is _____ ×10-1.             [2025]


Ans.

(16)

A2B2A++B2- 

i=1+(n-1)α 

One molecule of A2B dissociates into three particles, so n = 3.

α = 0.3 as per question.

i=1+(3-1)×0.3 

i=1.6=16×10-1