Arrange the following solutions in order of their increasing boiling points. [2025]

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Q.
Arrange the following solutions in order of their increasing boiling points. [2025]

(i) $10^{- 4}$ M NaCl
(ii) $10^{- 4}$ M Urea
(iii) $10^{- 3}$ M NaCl
(iv) $10^{- 2}$ M NaCl

1 (ii) < (i) ≡ (iii) < (iv)

2 (iv) < (iii) < (i) < (ii)

3 (ii) < (i) < (iii) < (iv)

4 (i) < (ii) < (iii) < (iv)

Ans.
(3)

$NaCl \to {Na}^{+} + {Cl}^{-}$

$i = 2$

Urea is non-electrolyte so, $i = 1$ .

Elevation in boiling point $Δ T_{b} = i k_{b} m .$ So higher is concentration and more is $i$ , more will be the boiling point.

Solution

Q.
Arrange the following solutions in order of their increasing boiling points. [2025]

(i) $10^{- 4}$ M NaCl
(ii) $10^{- 4}$ M Urea
(iii) $10^{- 3}$ M NaCl
(iv) $10^{- 2}$ M NaCl

1 (ii) < (i) ≡ (iii) < (iv)

2 (iv) < (iii) < (i) < (ii)

3 (ii) < (i) < (iii) < (iv)

4 (i) < (ii) < (iii) < (iv)

Ans.
(3)

$NaCl \to {Na}^{+} + {Cl}^{-}$

$i = 2$

Urea is non-electrolyte so, $i = 1$ .

Elevation in boiling point $Δ T_{b} = i k_{b} m .$ So higher is concentration and more is $i$ , more will be the boiling point.

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Solution

Q. Arrange the following solutions in order of their increasing boiling points. [2025] (i) 10-4M NaCl (ii) 10-4M Urea (iii) 10-3M NaCl (iv) 10-2M NaCl

1 (ii) < (i) ≡ (iii) < (iv)

2 (iv) < (iii) < (i) < (ii)

3 (ii) < (i) < (iii) < (iv)

4 (i) < (ii) < (iii) < (iv)

Ans. (3) NaCl→Na++Cl- i=2 Urea is non-electrolyte so, i=1. Elevation in boiling point ΔTb=ikbm. So higher is concentration and more is i, more will be the boiling point.

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Q.
Arrange the following solutions in order of their increasing boiling points. [2025]

(i) $10^{- 4}$ M NaCl
(ii) $10^{- 4}$ M Urea
(iii) $10^{- 3}$ M NaCl
(iv) $10^{- 2}$ M NaCl

Ans.
(3)

$NaCl \to {Na}^{+} + {Cl}^{-}$

$i = 2$

Urea is non-electrolyte so, $i = 1$ .

Elevation in boiling point $Δ T_{b} = i k_{b} m .$ So higher is concentration and more is $i$ , more will be the boiling point.