can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558. Assuming 100% ionisation of this complex and coordination number of Cr is 6, the complex will be (Given = 1.86 K kg )

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

Q.
${CrCl}_{3} \cdot {xNH}_{3}$ can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558 ${}^{o}C$ . Assuming 100% ionisation of this complex and coordination number of Cr is 6, the complex will be

(Given $K_{f}$ = 1.86 K kg ${mol}^{- 1}$ ) [2025]

1 $[Cr {({NH}_{3})}_{5} Cl] {Cl}_{2}$

2 $[Cr {({NH}_{3})}_{6}] {Cl}_{3}$

3 $[Cr {({NH}_{3})}_{3} {Cl}_{3}]$

4 $[Cr {({NH}_{3})}_{4} {Cl}_{2}] Cl$

Ans.
(1)

$Δ T_{f} = i k_{f} m$

$0.558 = i \times 1.86 \times 0.1$

$i = 3$

$[Cr {({NH}_{3})}_{5} Cl] {Cl}_{2} \to {[Cr {({NH}_{3})}_{5} Cl]}^{2 +} + 2 {Cl}^{-},$ $n = 3$

Solution

1 $[Cr {({NH}_{3})}_{5} Cl] {Cl}_{2}$

2 $[Cr {({NH}_{3})}_{6}] {Cl}_{3}$

3 $[Cr {({NH}_{3})}_{3} {Cl}_{3}]$

4 $[Cr {({NH}_{3})}_{4} {Cl}_{2}] Cl$

Ans.
(1)

$Δ T_{f} = i k_{f} m$

$0.558 = i \times 1.86 \times 0.1$

$i = 3$

$[Cr {({NH}_{3})}_{5} Cl] {Cl}_{2} \to {[Cr {({NH}_{3})}_{5} Cl]}^{2 +} + 2 {Cl}^{-},$ $n = 3$

Want Us to Email you About Special Offers & Updates?

Solution

Q. CrCl3·xNH3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558Co. Assuming 100% ionisation of this complex and coordination number of Cr is 6, the complex will be (Given Kf = 1.86 K kg mol-1) [2025]

1 [Cr(NH3)5Cl]Cl2

2 [Cr(NH3)6]Cl3

3 [Cr(NH3)3Cl3]

4 [Cr(NH3)4Cl2]Cl

Ans. (1) ΔTf=ikfm 0.558=i×1.86×0.1 i=3 [Cr(NH3)5Cl]Cl2 → [Cr(NH3)5Cl]2++2Cl-, n=3

Want Us to Email you About Special Offers & Updates?

1 $[Cr {({NH}_{3})}_{5} Cl] {Cl}_{2}$

2 $[Cr {({NH}_{3})}_{6}] {Cl}_{3}$

3 $[Cr {({NH}_{3})}_{3} {Cl}_{3}]$

4 $[Cr {({NH}_{3})}_{4} {Cl}_{2}] Cl$

Ans.
(1)

$Δ T_{f} = i k_{f} m$

$0.558 = i \times 1.86 \times 0.1$

$i = 3$

$[Cr {({NH}_{3})}_{5} Cl] {Cl}_{2} \to {[Cr {({NH}_{3})}_{5} Cl]}^{2 +} + 2 {Cl}^{-},$ $n = 3$