We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentration 0.1 M, 0.01 M and 0.001 M, respectively. The value of van’t Hoff factor (i) for these solutions will be in the order

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Solution

Q.
We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentration 0.1 M, 0.01 M and 0.001 M, respectively. The value of van’t Hoff factor (i) for these solutions will be in the order: [2024]

1 $i_{A} < i_{B} < i_{C}$

2 $i_{A} < i_{C} < i_{B}$

3 $i_{A} = i_{B} = i_{C}$

4 $i_{A} > i_{B} > i_{C}$

Ans.
(1)

Van't Hoff factor (i) is given by:

$i = \frac{Number of particles after dissociation}{Number of particles before dissociation}$

With dilution, degree of dissociation increases hence $i$ increases with dilution. Hence $i$ for A (0.1M NaCl), B (0.01M NaCl) and C (0.001M NaCl) is: $i_{A} < i_{B} < i_{C}$

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