Q 11 :    

The given figure represents two isobaric processes for the same mass of an ideal gas, then            [2024]

  • P1>P2

     

  • P2>P1

     

  • P1=P2

     

  • P2<P1

     

(1)

PV=nRTV=(nRP)T

Slope=nRPSlope1P

(Slope)2>(Slope)1P2<P1

 



Q 12 :    

For a particular ideal gas which of the following graphs represents the variation of mean squared velocity of the gas molecules with temperature?          [2025]

  •  

  •  

  •  

  •  

(1)

Mean squared velocity =(vms)2=3RTM i.e., (mean squared velocity)  (Temperature). Hence, graph is a straight line.



Q 13 :    

The ratio of vapour densities of two gases at the same temperature is 425, then the ratio of r.m.s. velocities will be:          [2025]

  • 254

     

  • 25

     

  • 52

     

  • 425

     

(3)

vrms=3RTM

v1v2=M2M1=254=52



Q 14 :    

Pressure of an ideal gas, contained in a closed vessel, is increased by 0.4% when heated by 1°C. Its initial temperature must be:          [2025]

  • 25°C

     

  • 2500 K

     

  • 250 K

     

  • 250°C

     

(3)

Isochoric process, P  T

PT=constant  PP=TT

0.4100=1T  T=1000.4=250 K



Q 15 :    

The mean free path and the average speed of oxygen molecules at 300 K and 1 atm are 3×107 m and 600 m/s, respectively. Find the frequency of its collisions.         [2025]

  • 2×1010/s

     

  • 9×105/s

     

  • 2×109/s

     

  • 5×102/s

     

(3)

Frequency of collision =average speedmean free path

                                            =6003×107=2×109/s



Q 16 :    

There are two vessels filled with an ideal gas where volume of one is double the volume of other. The large vessel contains the gas at 8 kPa at 1000 K while the smaller vessel contains the gas at 7 kPa at 500 K. If the vessels are connected to each other by a thin tube allowing the gas to flow and the temperature of both vessels is maintained at 600 K, at steady state the pressure in the vessels will be (in kPa).          [2025]

  • 4.4

     

  • 6

     

  • 24

     

  • 18

     

(2)

Number of masses will remain constant

n1+n2=nf

P1V1RT1=P2V2RT2=PfVfRTf

8×2VR×1000+7×VR×500=Pf(3V)R×600

161000+141000=Pf200

301000=Pf200  Pf=6 kPa



Q 17 :    

A container of fixed volume contains a gas at 27°C. To double the pressure of the gas, the temperature of gas should be raised to ________ °C.          [2025]



327

For V = constant, P1T1=P2T2

P300=2PT2

T2=600 K=327°C