Q 31 :

Let a1,a2,a3,… be an arithmetic progression. If a1+a2+⋯+a10a1+a2+⋯+aP=100P2 (where P≠0) then a11a10=

  • 1921

     

  • 10021

     

  • 2119

     

  • 121100

     

(3)

S10Sp=100p2⇒Sp=S10p2100,    a11a10=S11-S10S10-S9=2119



Q 32 :

If 7th and 13th terms of an A.P. be 34 and 64 respectively, then its 18th term is

  • 87

     

  • 88

     

  • 89

     

  • 90

     

(3)

Use an formula to find a = 4 and d = 5.



Q 33 :

If the ratio of the sum to n terms of two A.P.'s is (5n+3):(3n+4), then the ratio of their 4th terms is

  • 1623

     

  • 2316

     

  • 3825

     

  • 2538

     

(3)

Given n2[2a1+(n-1)d1]n2[2a2+(n-1)d2]=5n+33n+4

For n=7, a1+3d1a2+3d2=3825



Q 34 :

The first term of an A.P. of 30 non-negative terms is 103. If the sum of this A.P. is the cube of its last term, then its common difference is:          [2026]

  • 587

     

  • 2583

     

  • 1529

     

  • 529

     

(1)

We have, a=103

Then, l=103+29d

Given, S=l3

⇒ 302[203+29d]=(103+29d)3

⇒ 15[203+29d]=(103+29d)3

From options, d=587



Q 35 :

Let A1, A2, A3, ..., A39 be 39 arithmetic means between the numbers 59 and 159. Then the mean of A25, A28, A31 and A36 is equal to:          [2026]

  • 129

     

  • 136

     

  • 131.5

     

  • 134

     

(4)

Given 39 arithmetic means between 59 and 159.

So, sequence is 59, A1, A2, A3, ..., A39, 159,  (4! terms)

Common difference, d=159–5940=10040=52

∴  Ak=59+k·(52)

∴  A25=59+25(52)=121.5

A28=59+28(52)=129

A31=59+31(52)=136.5

A36=59+36(52)=149

∴  Mean=121.5+129+136.5+1494=134



Q 36 :

Let α = 3 + 4 + 8 + 9 + 13 + 14 + ... uto 40 terms. If (tanβ)α1020 is a root of the equation x2+x–2=0, β∈(0,π2), then sin2β+3cos2β is equal to:          [2026]

  • 2

     

  • 74

     

  • 52

     

  • 32

     

(1)

α=3+4+8+9+13+14+...(40 terms)

α=(3+8+13+...(20 terms)+(4+9+14+...(20 terms)

⇒ α=202[6+19×5]+202[8+19×5]

⇒ α=10[101+103]=2040

Now,  is a root of the equation.

⇒ x2+x–2=0

⇒ x2+2x–x–2=0

⇒ x=–2,1

∴  tan2β=1 ⇒β=π4

So, sin2β+3cos2β=12+32=2



Q 37 :

The number of common terms in the progressions 4, 9, 14, 19, ...... up to 25th term and 3, 6, 9, 12, ...... up to 35th term is _____

  • 9

     

  • 5

     

  • 7

     

  • 8

     

(3)

in 1st, 25th term is = 124 in 2nd, 35th term is = 105

Common terms are 9, 24, 39, 54, 69, 84, 99

Common difference is L.C.M of 5, 3