If A denotes the sum of all the coefficients in the expansion of (1-3x+10x2)n and B denotes the sum of all the coefficients in the expansion of (1+x2)n, then [2024]
B=A3
3A=B
A=3B
A=B3
(D)
Putting x=1 in (1-3x+10x2)n, we get
A=(1-3+10)n=8n ...(i)
Putting x=1 in (1+x2)n, we get
B=(1+1)n=2n ...(ii)
From (i) and (ii), we get A=B3
