Q.

The coefficient of x7 in (1-x+2x3)10 is _________ .             [2023]


Ans.

(960)

General term is given by

10!r1!r2!r3!(1)r1(-x)r2(2x3)r3 i.e., 10!r1!·r2!·r3!(-1)r2·(2)r3xr2+3r3

where r1+r2+r3=10 and r2+3r3=7

Possible values of (r1,r2,r3) are (3, 7, 0), (5, 4, 1) and (7, 1, 2)

Required coefficient

=10!3!7!(-1)7+10!5!4!(-1)4(2)+10!7!2!(-1)1(2)2

=-120+2520-1440=960