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Q 1 :

The number of incorrect statement/s from the following is ______. [2023]

A. The successive half-lives of zero-order reactions decrease with time.

B. A substance appearing as reactant in the chemical equation may not affect the rate of reaction.

C. Order and molecularity of a chemical reaction can be a fractional number.

D. The rate constant units of zero and second order reaction are mol $L^{- 1} s^{- 1}$ and ${mol}^{- 1}$ L $s^{- 1}$ respectively.

0%

(1)

(A) For zero order, $t_{1 / 2} = \frac{[A_{0}]}{2 K},$ as time decreases, concentration decreases and hence, half-life decreases. (correct)

(B) If order w.r.t. that reactant is zero, then it will not affect the rate of reaction. (correct)

(C) Order can be fractional but molecularity cannot be. (Incorrect)

(D) Unit of $K = {(mol)}^{1 - n} L t^{n - 1} s^{- 1}$

$n = 0,$ $K = mol L^{- 1} s^{- 1};$ $n = 2$ , $K = {mol}^{- 1} Lt s^{- 1} .$ (correct)

Q 2 :

An organic compound undergoes first order decomposition. The time taken for decomposition to ${((\frac{1}{8}))}^{th}$ and ${((\frac{1}{10}))}^{th}$ of its initial concentration are $t_{1 / 8}$ and $t_{1 / 10}$ respectively.

What is the value of $\frac{t_{1 / 8}}{t_{1 / 10}} \times 10 ?$

$(\log 2 = 0.3)$ [2026]

(1)

$t = \frac{1}{k} \ln \frac{A_{0}}{A_{t}}$

$t_{1 / 8} = \frac{1}{k} \ln \frac{A_{0}}{A_{0} / 8} = \frac{1}{k} \ln 8$

$t_{1 / 10} = \frac{1}{k} \ln \frac{A_{0}}{A_{0} / 10} = \frac{1}{k} \ln 10$

$\frac{t_{1 / 8}}{t_{1 / 10}} = \frac{\ln 8}{\ln 10} = \frac{\log 8}{\log 10}$

$\frac{t_{1 / 8}}{t_{1 / 10}} = \log 8 = 3 \log 2 = 0.9$

$\frac{t_{1 / 8}}{t_{1 / 10}} \times 10 = 9$

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Q 2 : An organic compound undergoes first order decomposition. The time taken for decomposition to (18)th and (110)th of its initial concentration are t1/8 and t1/10 respectively. What is the value of t1/8t1/10×10 ? (log2=0.3) [2026]

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