Q 21 :

If 917 Å be the lowest wavelength of Lyman series then the lowest wavelength of Balmer series will be _________ Å.                [2023]



(3668)

For lowest wavelength of Lyman series,    1λ=RZ2[112-12]=RZ2

For lowest wavelength of Balmer series,    1λ'=RZ2[122-12]=RZ24

λ'=4RZ2=4×917=3668 Å



Q 22 :

A monochromatic light is incident on a hydrogen sample in ground state. Hydrogen atoms absorb a fraction of light and subsequently emit radiation of six different wavelengths. The frequency of incident light is x×1015Hz. The value of x is _______. (Given h=4.25×10-15eVs)                   [2023]



(3)

6=C24  n2=4

hν=E4-E1

 ν=13.6(112-142)×14.25×10-15=3×1015 Hz



Q 23 :

An atom absorbs a photon of wavelength 500 nm and emits another photon of wavelength 600 nm. The net energy absorbed by the atom in this process is n×10-4eV. The value of n is ________.                  [2023]

[Assume the atom to be stationary during the absorption and emission process]

(Take h=6.6×10-34Js and c=3×108m/s)                     



(4125)

E=E1-E2=hcλ1-hcλ2=hc(1λ1-1λ2)

=6.6×10-34×3×108(1500×10-9-1600×10-9)

=6.6×10-20 J

=6.6×10-201.6×10-19 eV=4.125×10-1 eV=4125×10-4 eV



Q 24 :

As per given figure A, B and C are the first, second and third excited energy level of hydrogen atom respectively. If the ratio of the two wavelengths (i.e., λ1λ2) is 74n, then the value of n will be _______.                [2023]



(5)

As    1λ=RZ2[1n12-1n22]

1λ1=R(1)2[1(2)2-1(3)2]=R(536)    (i)

1λ2=R(1)2[1(3)2-1(4)2]=R(7144)    (ii)

(ii) + (i) gives

λ1λ2=7144536=720=74×5

 n=5



Q 25 :

The smallest wavelength of Lyman series is 91 nm. The difference between the largest wavelengths of Paschen and Balmer series is nearly ______ nm.       [2026]

  • 1217

     

  • 1550

     

  • 1784

     

  • 1875

     

(1)