Which will make basic buffer? [2019]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

Q.
Which will make basic buffer [2019]

1 100 mL of 0.1 M HCl + 100 mL of 0.1 M NaOH

2 50 mL of 0.1 M NaOH + 25 mL of 0.1 M ${CH}_{3} COOH$

3 100 mL of 0.1 M ${CH}_{3} COOH$ + 100 mL of 0.1 M NaOH

4 100 mL of 0.1 M HCl + 200 mL of 0.1 M ${NH}_{4} OH$

Ans.
(4)

Acid-base titration:

$\underset{10 mmol}{HCl} + \underset{20 mmol}{{NH}_{4} OH} \to {NH}_{4} Cl$

$∴$ HCl is the limiting reagent.

Solution contains ${NH}_{4} OH$ (weak base) and ${NH}_{4} Cl$ (salt of strong acid and weak base). Therefore, a basic buffer will be formed.

Solution

Q. Which will make basic buffer [2019]

1 100 mL of 0.1 M HCl + 100 mL of 0.1 M NaOH

2 50 mL of 0.1 M NaOH + 25 mL of 0.1 M CH3COOH

3 100 mL of 0.1 M CH3COOH + 100 mL of 0.1 M NaOH

4 100 mL of 0.1 M HCl + 200 mL of 0.1 M NH4OH

Ans. (4) Acid-base titration: HCl10 mmol+NH4OH20 mmol→NH4Cl ∴ HCl is the limiting reagent. Solution contains NH4OH (weak base) and NH4Cl (salt of strong acid and weak base). Therefore, a basic buffer will be formed.

Want Us to Email you About Special Offers & Updates?

Q.
Which will make basic buffer [2019]

2 50 mL of 0.1 M NaOH + 25 mL of 0.1 M ${CH}_{3} COOH$

3 100 mL of 0.1 M ${CH}_{3} COOH$ + 100 mL of 0.1 M NaOH

4 100 mL of 0.1 M HCl + 200 mL of 0.1 M ${NH}_{4} OH$

Ans.
(4)

Acid-base titration:

$\underset{10 mmol}{HCl} + \underset{20 mmol}{{NH}_{4} OH} \to {NH}_{4} Cl$

$∴$ HCl is the limiting reagent.

Solution contains ${NH}_{4} OH$ (weak base) and ${NH}_{4} Cl$ (salt of strong acid and weak base). Therefore, a basic buffer will be formed.