Which one of the followings has maximum number of atoms? [2020]

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Q.
Which one of the followings has maximum number of atoms [2020]

1 1 g of ${Ag}_{(s)}$ [Atomic mass of Ag = 108]

2 1 g of ${Mg}_{(s)}$ [Atomic mass of Mg = 24]

3 1 g of $O_{2 (g)}$ [Atomic mass of O = 16]

4 1 g of ${Li}_{(s)}$ [Atomic mass of Li = 7]

Ans.
(4)

1 mole of substance $= N_{A}$ atoms

108 g of Ag $= N_{A}$ atoms $\Rightarrow$ 1 g of Ag $= \frac{N_{A}}{108}$ atoms

24 g of Mg $= N_{A}$ atoms $\Rightarrow$ 1 g of Mg $= \frac{N_{A}}{24}$ atoms

32 g of $O_{2} = N_{A}$ molecules $= 2 N_{A}$ atoms

$\Rightarrow$ 1 g of $O_{2} = \frac{N_{A}}{16}$ atoms

7 g of Li $= N_{A}$ atoms $\Rightarrow$ 1 g of Li $= \frac{N_{A}}{7}$ atoms

Therefore, 1 g of ${Li}_{(s)},$ has maximum number of atoms.

Solution

Q.
Which one of the followings has maximum number of atoms [2020]

1 1 g of ${Ag}_{(s)}$ [Atomic mass of Ag = 108]

2 1 g of ${Mg}_{(s)}$ [Atomic mass of Mg = 24]

3 1 g of $O_{2 (g)}$ [Atomic mass of O = 16]

4 1 g of ${Li}_{(s)}$ [Atomic mass of Li = 7]

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Solution

Q. Which one of the followings has maximum number of atoms [2020]

1 1 g of Ag(s) [Atomic mass of Ag = 108]

2 1 g of Mg(s) [Atomic mass of Mg = 24]

3 1 g of O2(g) [Atomic mass of O = 16]

4 1 g of Li(s) [Atomic mass of Li = 7]

Ans. (4) 1 mole of substance =NA atoms 108 g of Ag =NA atoms ⇒ 1 g of Ag =NA108 atoms 24 g of Mg =NA atoms ⇒ 1 g of Mg =NA24 atoms 32 g of O2=NA molecules =2NA atoms ⇒ 1 g of O2=NA16 atoms 7 g of Li =NA atoms ⇒ 1 g of Li =NA7 atoms Therefore, 1 g of Li(s), has maximum number of atoms.

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Q.
Which one of the followings has maximum number of atoms [2020]

1 1 g of ${Ag}_{(s)}$ [Atomic mass of Ag = 108]

2 1 g of ${Mg}_{(s)}$ [Atomic mass of Mg = 24]

3 1 g of $O_{2 (g)}$ [Atomic mass of O = 16]

4 1 g of ${Li}_{(s)}$ [Atomic mass of Li = 7]