Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules? [2016]

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Q.
Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules [2016]

1 ${Br}_{2} > I_{2} > F_{2} > {Cl}_{2}$

2 $F_{2} > {Cl}_{2} > {Br}_{2} > I_{2}$

3 $I_{2} > {Br}_{2} > {Cl}_{2} > F_{2}$

4 ${Cl}_{2} > {Br}_{2} > F_{2} > I_{2}$

Ans.
(4)

The order of bond dissociation enthalpy is:

$\begin{matrix} {Cl}_{2} & > & {Br}_{2} & > \\ B . E . (in kJ {mol}^{- 1}) & 242.6 & 192.8 \end{matrix} \begin{matrix} F_{2} & > & I_{2} \\ 158.8 & 151.1 \end{matrix}$

A reason for this anomaly is the relatively large electron–electron repulsion among the lone pairs in $F_{2}$ molecule where they are much closer to each other than in case of ${Cl}_{2}$ .

Solution

Q.
Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules [2016]

1 ${Br}_{2} > I_{2} > F_{2} > {Cl}_{2}$

2 $F_{2} > {Cl}_{2} > {Br}_{2} > I_{2}$

3 $I_{2} > {Br}_{2} > {Cl}_{2} > F_{2}$

4 ${Cl}_{2} > {Br}_{2} > F_{2} > I_{2}$

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Solution

Q. Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules [2016]

1 Br2>I2>F2>Cl2

2 F2>Cl2>Br2>I2

3 I2>Br2>Cl2>F2

4 Cl2>Br2>F2>I2

Ans. (4) The order of bond dissociation enthalpy is: Cl2>Br2>B.E. (in kJ mol-1)242.6192.8F2>I2158.8151.1 A reason for this anomaly is the relatively large electron–electron repulsion among the lone pairs in F2 molecule where they are much closer to each other than in case of Cl2.

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Q.
Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules [2016]

1 ${Br}_{2} > I_{2} > F_{2} > {Cl}_{2}$

2 $F_{2} > {Cl}_{2} > {Br}_{2} > I_{2}$

3 $I_{2} > {Br}_{2} > {Cl}_{2} > F_{2}$

4 ${Cl}_{2} > {Br}_{2} > F_{2} > I_{2}$