• 072920 77839
  • info@smartachievers.in
Menu
Back
  • JEE ADVANCE
  • JEE MAIN
  • NEET
  • BITSAT
  • CBSE BOARD
  • UP BOARD
  • CUET
JEE ADVANCE
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
JEE MAIN
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
NEET
  • CLASS XI - XII
  • CRASH COURSE
BITSAT
  • CLASS XI - XII
CBSE BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
  • CLASS VI
  • CLASS VII
  • CLASS VIII
UP BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
CUET
  • CRASH COURSE
Courses


Solution


Q.

Which of the following statements is correct regarding a solution of two components A and B exhibiting positive deviation from ideal behaviour            [2019]
1 Intermolecular attractive forces between A–A and B–B are stronger than those between A–B.  
2 ΔmixH = 0 at constant T and P.  
3 ΔmixV = 0 at constant T and P.  
4 Intermolecular attractive forces between A–A and B–B are equal to those between A–B.  

Ans.

(1)

In case of positive deviation from Raoult’s law, A–B interactions are weaker than those between A–A or B–B, i.e., in this case the intermolecular attractive forces between the solute–solvent molecules are weaker than those between the solute–solute and solvent–solvent molecules. This means that in such solutions, molecules of A (or B) will find it easier to escape than in pure state. This will increase the vapour pressure and result in positive deviation.