Which of the following statements is correct for the spontaneous adsorption of a gas? [2014]

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Q.
Which of the following statements is correct for the spontaneous adsorption of a gas [2014]

1 $Δ S$ is negative and, therefore $Δ H$ should be highly positive.

2 $Δ S$ is negative and therefore, $Δ H$ should be highly negative.

3 $Δ S$ is positive and therefore, $Δ H$ should be negative.

4 $Δ S$ is positive and therefore, $Δ H$ should also be highly positive.

Ans.
(2)

Using Gibbs'-Helmholtz equation,

$Δ G = Δ H - T Δ S$

During adsorption of a gas, entropy decreases i.e., $Δ S < 0$

For spontaneous adsorption, $Δ G$ should be negative, which is possible when $Δ H$ is highly negative.

Solution

Q.
Which of the following statements is correct for the spontaneous adsorption of a gas [2014]

1 $Δ S$ is negative and, therefore $Δ H$ should be highly positive.

2 $Δ S$ is negative and therefore, $Δ H$ should be highly negative.

3 $Δ S$ is positive and therefore, $Δ H$ should be negative.

4 $Δ S$ is positive and therefore, $Δ H$ should also be highly positive.

Ans.
(2)

Using Gibbs'-Helmholtz equation,

$Δ G = Δ H - T Δ S$

During adsorption of a gas, entropy decreases i.e., $Δ S < 0$

For spontaneous adsorption, $Δ G$ should be negative, which is possible when $Δ H$ is highly negative.

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Solution

Q. Which of the following statements is correct for the spontaneous adsorption of a gas [2014]

1 ΔS is negative and, therefore ΔH should be highly positive.

2 ΔS is negative and therefore, ΔH should be highly negative.

3 ΔS is positive and therefore, ΔH should be negative.

4 ΔS is positive and therefore, ΔH should also be highly positive.

Ans. (2) Using Gibbs'-Helmholtz equation, ΔG=ΔH-TΔS During adsorption of a gas, entropy decreases i.e., ΔS<0 For spontaneous adsorption, ΔG should be negative, which is possible when ΔH is highly negative.

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Q.
Which of the following statements is correct for the spontaneous adsorption of a gas [2014]

1 $Δ S$ is negative and, therefore $Δ H$ should be highly positive.

2 $Δ S$ is negative and therefore, $Δ H$ should be highly negative.

3 $Δ S$ is positive and therefore, $Δ H$ should be negative.

4 $Δ S$ is positive and therefore, $Δ H$ should also be highly positive.

Ans.
(2)

Using Gibbs'-Helmholtz equation,

$Δ G = Δ H - T Δ S$

During adsorption of a gas, entropy decreases i.e., $Δ S < 0$

For spontaneous adsorption, $Δ G$ should be negative, which is possible when $Δ H$ is highly negative.