Which is the correct thermal stability order for H2E (E = O, S, Se, Te and Po)? [2019]

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Q.
Which is the correct thermal stability order for $H_{2} E$ (E = O, S, Se, Te and Po) [2019]

1 $H_{2} Se < H_{2} Te < H_{2} Po < H_{2} O < H_{2} S$

2 $H_{2} S < H_{2} O < H_{2} Se < H_{2} Te < H_{2} Po$

3 $H_{2} O < H_{2} S < H_{2} Se < H_{2} Te < H_{2} Po$

4 $H_{2} Po < H_{2} Te < H_{2} Se < H_{2} S < H_{2} O$

Ans.
(4)

The thermal stability of hydrides decreases from $H_{2} O$ to $H_{2} Po$ . This is because as the size of atom E in $H_{2} E$ increases, the bond H–E becomes weaker and thus, breaks on heating. Therefore, the correct order of thermal stability is $H_{2} Po < H_{2} Te < H_{2} Se < H_{2} S < H_{2} O .$

Solution

Q.
Which is the correct thermal stability order for $H_{2} E$ (E = O, S, Se, Te and Po) [2019]

1 $H_{2} Se < H_{2} Te < H_{2} Po < H_{2} O < H_{2} S$

2 $H_{2} S < H_{2} O < H_{2} Se < H_{2} Te < H_{2} Po$

3 $H_{2} O < H_{2} S < H_{2} Se < H_{2} Te < H_{2} Po$

4 $H_{2} Po < H_{2} Te < H_{2} Se < H_{2} S < H_{2} O$

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Solution

Q. Which is the correct thermal stability order for H2E (E = O, S, Se, Te and Po) [2019]

1 H2Se<H2Te<H2Po<H2O<H2S

2 H2S<H2O<H2Se<H2Te<H2Po

3 H2O<H2S<H2Se<H2Te<H2Po

4 H2Po<H2Te<H2Se<H2S<H2O

Ans. (4) The thermal stability of hydrides decreases from H2O to H2Po. This is because as the size of atom E in H2E increases, the bond H–E becomes weaker and thus, breaks on heating. Therefore, the correct order of thermal stability is H2Po<H2Te<H2Se<H2S<H2O.

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Q.
Which is the correct thermal stability order for $H_{2} E$ (E = O, S, Se, Te and Po) [2019]

1 $H_{2} Se < H_{2} Te < H_{2} Po < H_{2} O < H_{2} S$

2 $H_{2} S < H_{2} O < H_{2} Se < H_{2} Te < H_{2} Po$

3 $H_{2} O < H_{2} S < H_{2} Se < H_{2} Te < H_{2} Po$

4 $H_{2} Po < H_{2} Te < H_{2} Se < H_{2} S < H_{2} O$