Q.

When ΔHvap=30kJ/mol and Svap=75J mol-1 K-1, then the temperature of vapour, at one atmosphere is ___________ K.      [2024]


Ans.

(400) 

When external pressure is 1 atm ,then vapours are formed at normal boiling point of the liquid. So in the question, normal boiling point of the liquid is asked.

ΔSvap=ΔHvapTbpt

75J mol-1K-1=30×1000Jmol-1Tbpt

Tbpt=400K