When ion is treated with , a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound Y is formed. X and Y respectively are: [2023]

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Q.
When ${Cu}^{2 +}$ ion is treated with $KI$ , a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound Y is formed. X and Y respectively are: [2023]

1 $X = {CuI}_{2}$ $Y = {Na}_{2} S_{2} O_{3}$

2 $X = {CuI}_{2}$ $Y = {Na}_{2} S_{4} O_{6}$

3 $X = {Cu}_{2} I_{2}$ $Y = {Na}_{2} S_{4} O_{6}$

4 $X = {Cu}_{2} I_{2}$ $Y = {Na}_{2} S_{4} O_{5}$

Ans.
(3)

${Cu}^{2 +} + 4 I^{-} ⟶ \underset{\underset{' X'}{White}}{{Cu}_{2} I_{2}} + I_{2}$

$I_{2} + 2 {Na}_{2} S_{2} O_{3} ⟶ \underset{' Y'}{2 {Na}_{2} S_{4} O_{6}} + 2 NaI$

$X = {Cu}_{2} I_{2}$ and $Y = {Na}_{2} S_{4} O_{6}$

Solution

Q.
When ${Cu}^{2 +}$ ion is treated with $KI$ , a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound Y is formed. X and Y respectively are: [2023]

1 $X = {CuI}_{2}$ $Y = {Na}_{2} S_{2} O_{3}$

2 $X = {CuI}_{2}$ $Y = {Na}_{2} S_{4} O_{6}$

3 $X = {Cu}_{2} I_{2}$ $Y = {Na}_{2} S_{4} O_{6}$

4 $X = {Cu}_{2} I_{2}$ $Y = {Na}_{2} S_{4} O_{5}$

Ans.
(3)

${Cu}^{2 +} + 4 I^{-} ⟶ \underset{\underset{' X'}{White}}{{Cu}_{2} I_{2}} + I_{2}$

$I_{2} + 2 {Na}_{2} S_{2} O_{3} ⟶ \underset{' Y'}{2 {Na}_{2} S_{4} O_{6}} + 2 NaI$

$X = {Cu}_{2} I_{2}$ and $Y = {Na}_{2} S_{4} O_{6}$

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Solution

Q. When Cu2+ ion is treated with KI, a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound Y is formed. X and Y respectively are: [2023]

1 X=CuI2 Y=Na2S2O3

2 X=CuI2 Y=Na2S4O6

3 X=Cu2I2 Y=Na2S4O6

4 X=Cu2I2 Y=Na2S4O5

Ans. (3) Cu2++4I-⟶Cu2I2White'X'+I2 I2+2Na2S2O3⟶2Na2S4O6'Y'+2NaI X=Cu2I2 and Y=Na2S4O6

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Q.
When ${Cu}^{2 +}$ ion is treated with $KI$ , a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound Y is formed. X and Y respectively are: [2023]

1 $X = {CuI}_{2}$ $Y = {Na}_{2} S_{2} O_{3}$

2 $X = {CuI}_{2}$ $Y = {Na}_{2} S_{4} O_{6}$

3 $X = {Cu}_{2} I_{2}$ $Y = {Na}_{2} S_{4} O_{6}$

4 $X = {Cu}_{2} I_{2}$ $Y = {Na}_{2} S_{4} O_{5}$

Ans.
(3)

${Cu}^{2 +} + 4 I^{-} ⟶ \underset{\underset{' X'}{White}}{{Cu}_{2} I_{2}} + I_{2}$

$I_{2} + 2 {Na}_{2} S_{2} O_{3} ⟶ \underset{' Y'}{2 {Na}_{2} S_{4} O_{6}} + 2 NaI$

$X = {Cu}_{2} I_{2}$ and $Y = {Na}_{2} S_{4} O_{6}$