When a hydrocarbon A undergoes combustion in the presence of air, it requires 9.5 equivalents of oxygen and produces 3 equivalents of water. What is the molecular formula of A? [2023]

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Solution

Q.
When a hydrocarbon A undergoes combustion in the presence of air, it requires 9.5 equivalents of oxygen and produces 3 equivalents of water. What is the molecular formula of A [2023]

1 $C_{9} H_{6}$

2 $C_{6} H_{6}$

3 $C_{8} H_{6}$

4 $C_{9} H_{9}$

Ans.
(3)

$C_{x} H_{y} + (x + \frac{y}{4}) O_{2} ⟶ x C O_{2} + \frac{y}{2} H_{2} O$

$No. of equivalents of O_{2} = No. of equivalents of H_{2} O$

$No. of equivalents of H_{2} O = \frac{y}{2} = 3$

$y = 6$

$No. of equivalents of O_{2} = x + \frac{y}{4} = 9.5$

$x = 9.5 - 1.5 = 8$

$C_{x} H_{y} = C_{8} H_{6}$

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