Q.

When 0.1 mol MnO42- is oxidised, the quantity of electricity required to completely oxidise MnO42- to MnO4- is             [2014]

1 96500 C  
2 2×96500 C  
3 9650 C  
4 96.50 C  

Ans.

(3)

The oxidation reaction is

M+6nO42-0.1 mol M+7nO4-0.1 mol+e-

Q=0.1×F=0.1×96500 C=9650 C