When 0.1 mol MnO42- is oxidised, the quantity of electricity required to completely oxidise MnO42- to MnO4- is [2014]
(3)
The oxidation reaction is
M+6nO42-0.1 mol →M+7nO4-0.1 mol+e-
Q=0.1×F=0.1×96500 C=9650 C