When 0.01 mol of an organic compound containing 60% carbon was burnt completely, 4.4 g of was produced. The molar mass of compound is ______ g (Nearest integer). [2023]

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Solution

Q.
When 0.01 mol of an organic compound containing 60% carbon was burnt completely, 4.4 g of ${CO}_{2}$ was produced. The molar mass of compound is ______ g ${mol}^{- 1}$ (Nearest integer). [2023]

Ans.
(200)

$Let M = Molar mass of the compound$

$Mass of carbon = 0.01 M \times \frac{60}{100}$

$Mole of carbon = \frac{0.01 M}{12} \times \frac{60}{100}$

${Mole of CO}_{2} from combustion = \frac{4.4}{44} = mole of carbon$

$\frac{0.01 M}{12} \times \frac{60}{100} = \frac{4.4}{44}$ $\Rightarrow M = \frac{4.4}{44} \times \frac{100}{60} \times \frac{12}{0.01} = 200 g/mol$

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