What is the mass of the precipitate formed when 50 mL of 16.9% solution of is mixed with 50 mL of 5.8% NaCl solution? (Ag = 107.8, N = 14, O = 16, Na = 23, Cl = 35.5) [2015]

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Solution

Q.
What is the mass of the precipitate formed when 50 mL of 16.9% solution of ${AgNO}_{3}$ is mixed with 50 mL of 5.8% NaCl solution

(Ag = 107.8, N = 14, O = 16, Na = 23, Cl = 35.5) [2015]

1 3.5 g

2 7 g

3 14 g

4 28 g

Ans.
(2)

16.9% solution of $A g N O_{3}$ means 16.9 g of $A g N O_{3}$ in 100 mL of solution $= {8.45 g of AgNO}_{3} in 50 mL solution.$

Similarly, 5.8 g of NaCl in 100 mL solution $\equiv 2.9 g of NaCl in 50 mL solution.$

The reaction can be represented as:

$∴$ $Mass of AgCl precipitated = 0.049 \times 143.5 = 7.03 \approx 7$ $g$

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