What amount of bromine will be required to convert 2 g of phenol into 2,4,6-tribromophenol? : (Given molar mass in g of C, H, O, Br are 12, 1, 16, 80 respectively) [2025]

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Solution

Q.
What amount of bromine will be required to convert 2 g of phenol into 2,4,6-tribromophenol :

(Given molar mass in g ${mol}^{- 1}$ of C, H, O, Br are 12, 1, 16, 80 respectively) [2025]

1 6.0 g

2 20.44 g

3 10.22 g

4 4.0 g

Ans.
(3)

$Moles of phenol = \frac{Given mass}{Molar mass} = \frac{2}{94} mol$

By stoichiometry of the reaction,

$Moles of {Br}_{2} = 3 \times Moles of phenol = 3 \times \frac{2}{94} mol$

$Mass of bromine = Moles of {Br}_{2} \times Molar mass of {Br}_{2}$

$Mass of bromine = 3 \times \frac{2}{94} mol \times 160 {g mol}^{- 1} = 10.21 g$

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