Vectors ai^+bj^+k^ and 2i^–3j^+4k^ are perpendicular to each other when 3a + 2b = 7, the ratio of a to b is x2. The value of x is ________ . [2023]
(1)
For two perpendicular vectors
(ai^+bj^+k^)·(2i^–3j^+4k^)=0
2a – 3b + 4 = 0
on solving, 2a – 3b = –4
also given 3a + 2b = 7
We get a = 1, b = 2
ab=x2 ⇒ x=2ab=2×12=1