Two slits in Young’s double slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is m, then the fringe separation is [2024]

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Solution

Q.
Two slits in Young’s double slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is $600 \times 10^{- 9}$ m, then the fringe separation is [2024]

1 $4 \times 10^{- 5}$ m

2 $9 \times 10^{- 8}$ m

3 $4 \times 10^{- 7}$ m

4 $4 \times 10^{- 4}$ m

Ans.
(4)

Slit separation distance, $d = 1.5 mm = 1.5 \times 10^{- 3} m$

Slit and screen separation distance, $D = 1$ $m$

Wavelength, $λ = 600 \times 10^{- 9}$ $m$

Fringe separation $= \frac{λ D}{d} = \frac{600 \times 10^{- 9} \times 1}{1.5 \times 10^{- 3}} = 4 \times 10^{- 4}$ $m$

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