Q.

Two objects are projected with same velocity 'u' however at different angles α and β with the horizontal. If α+β=90°, the ratio of horizontal range of the first object to the second object will be              [2023]

1 1 : 2  
2 4 : 1  
3 2 : 1  
4 1 : 1  

Ans.

(4)

Range=u2sin2θg

Range for projection angle ''α''

         R1=u2sin2αg

Range for projection angle ''β''

         R2=u2sin2βg

α+β=90° (given)  β=90°-α

R2=u2sin2(90°-α)g

R2=u2sin(180°-2α)g

R2=u2sin2αg

  R1R2=(u2sin2αg)(u2sin2αg)=11