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Solution


Q.

Two dice are thrown together. The probability that they show different numbers is:
1 1/6  
2 5/6  
3 1/3  
4 2/3  

Ans.

(2)

When two dice are thrown together, the possible outcomes are:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).

Therefore, the total number of possible outcomes = 36 ⇒n(S)=36

Let E be the event of getting different numbers on dice.

n(E)=30=36-6

P(E)=n(E)n(S) =3036=56