Two cells are connected in opposition as shown. Cell is of 8 V emf and internal resistance; the cell is of 2 V emf and internal resistance. The terminal potential difference of cell is ____ V.

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Solution

Q.
Two cells are connected in opposition as shown. Cell $E_{1}$ is of 8 V emf and $2 Ω$ internal resistance; the cell $E_{2}$ is of 2 V emf and $4 Ω$ internal resistance. The terminal potential difference of cell $E_{2}$ is ____ V. [2024]

Ans.
(6)

$r_{eq} = r_{1} + r_{2} = (2 + 4) Ω = 6 Ω$

Current in the loop, $i = \frac{ε_{eq}}{r_{eq}} = \frac{6 V}{6 Ω} = 1 A$

Terminal potential difference of cell $E_{2} \Rightarrow E_{2} + i r_{2}$

$\Rightarrow [2 + (1) (4)] V \Rightarrow 6 V$

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