Time intervals measured by a clock give the following readings: 1.25 s, 1.24 s, 1.27 s, 1.21 s and 1.28 s
What is the percentage relative error of the observations
a) t¯=1.25+1.24+1.27+1.21+1.285
=1.25S
(∆t)1=1.25-1.25=0
(∆t)2=1.24 - 1.25 =-0.01
(∆t)3=1.27 -1.25 = 0.02
(∆t)4=1.21 - 1.25 =-0.04
(∆t)5=1.28 - 1.25 = 0.03
|∆t¯|=|(∆t)1|+|(∆t)2|+|(∆t)3|+|(∆t)4|+|(∆t)5|5
=0+0.01+0.02+0.04+ 0.03 5=0.02
|∆t¯|t¯×100=0.021.25×100=1.6%