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Solution


Q.

Three moles of an ideal gas are compressed isothermally from 60 L to 20 L using constant pressure of 5 atm. Heat exchange Q for the compression is – ________ Lit. atm.   [2024]

Ans.

(200)

w=-PextΔV=-Pext(V2-V1)=-5(20-60) atm L=200 atm L

By first law of thermodynamics:

ΔV=-w+q

For isothermal process, ΔU=0, so q=-w=-200 atm L